2(2x+7)=5(32^x+3)

Simple and best practice solution for 2(2x+7)=5(32^x+3) equation. Check how easy it is, and learn it for the future. Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework.

If it's not what You are looking for type in the equation solver your own equation and let us solve it.

Solution for 2(2x+7)=5(32^x+3) equation: 



2(2x+7)=5(32^x+3)

We move all terms to the left:

2(2x+7)-(5(32^x+3))=0

We multiply parentheses

4x-(5(32^x+3))+14=0



We calculate terms in parentheses: -(5(32^x+3)), so:

5(32^x+3)

We multiply parentheses

160x+15

Back to the equation:

-(160x+15)



We get rid of parentheses

4x-160x-15+14=0

We add all the numbers together, and all the variables

-156x-1=0

We move all terms containing x to the left, all other terms to the right

-156x=1

x=1/-156

x=-1/156

See similar equations:

| 7x/10=x/3+11 | | 2.2=4.5c-0.5 | | D^2-5D-6y=0 | | (5x-9)^2=3 | | 3•-3-4y=23 | | m=-1/4;(9,0) | | -(x+5)=-10-4 | | 9x^2-20x-86=0 | | 7x+5=-93 | | 9x^2-20x+86=0 | | (X-2)(x-2)(x-2)=8 | | 1^5x+4^5x=2 | | 4x-3/2x+6=3 | | 1681=41a | | 112t-16t^2-96=0 | | 8x^2-7x-46=0 | | 8x^2-7x+46=0 | | 267.89=(0.07m+29.70+0.10(29.70)) | | z+3=29−2zz+3=29−2z | | 3d−12=9d= | | 20y=4y= | | 3x-2x^2-7=0 | | 64.4=7(m+3.1) | | x26=3 | | 1+2x-x-1=3-x-3+x | | (6+z)(2z-7)=0 | | (4m-1)^2=0 | | 29=6+k | | -5x(x-3)(5x+9)^2=0 | | (x+14)^3/2-15=12 | | 28=12+k | | h/6​​−1=−3 |

Equations solver categories